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2 years ago

What is the name of the parent function for f(x)=2 x-1

Mathematics

1 answer:

Over [174]2 years ago

6 0

Answer:

Linear Function

Step-by-step explanation:

Any equeation that comes in the form mx + b is a linear function

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Find the area of this acute triangle

professor190 [17]

$a = \frac{1}{2} bh$

$a = \frac{1}{2} (10)(5)$

$a = \frac{1}{2} (50)$

$a = 25 \: {m}^{2}$

3 0

2 years ago

This is my question

Talja [164]

Answer/Step-by-step explanation:

∆ABC is similar to ∆CDE. Therefore, the ratio of their corresponding sides are proportional.

This,

$\frac{DE}{AB} = \frac{DC}{AC}$

$\frac{4}{3} = \frac{x + 3}{x + 1}$

Solve for x

$4(x + 1) = 3(x + 3)$

$4x + 4 = 3x + 9$

$4x + 4 - 4 = 3x + 9 - 4$

$4x = 3x + 5$

$4x - 3x = 3x + 5 - 3x$

$x = 5$

Use the value of x to find AC and DC

$AC = x + 1 = 5 + 1 = 6$

$DC = x + 3 = 5 + 3 = 8$

4 0

2 years ago

If f(x) = x2 – 2x, find: X - f(-3) = [?]

Reptile [31]

Did you mean :

f(x) = x² - 2x, find x = -3

f(-3) = (-3)² - 2(-3)

f(-3) = 9 + 6

f(-3) = 15

6 0

2 years ago

A staff has lines and spaces.

Lisa [10]

Answer:

That's true. It does have 5 lines and 4 spaces.

Step-by-step explanation:

Ion know if it's a true or false question but I hope I helped ya.

If you don't understand my answer, hmu in the comments.

< Sarah >

6 0

2 years ago

Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x

Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

$f(x) = (x - (7 + i)) (x - (5 - i))$

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

$f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))$

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

$f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48$

5 0

1 year ago