Answer:
Last option is the correct choice.
Explanation:
Number of protons = 60-33 = 27
Superscript 60 Subscript 27 upper C o.
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The answers are a.) 0.03 mol KOH requires 0.03 mol HCl, b.) 2 mol NH3 requires 2 mol HCl and c.) 0.1 mol Ca(OH)2 requires 0.2 mol HCl.
Solution:
We need to write the balanced equations for each reactions to find out the stoichiometry for each reactants.
a.) HCl (aq) + KOH (aq) → KCl (aq) + H2O(ℓ)
From the balanced equations, we can see that 1 HCl reacts with 1 KOH, therefore if 0.03 mol KOH is reacted then 0.03 mol HCl must also be present.
b.) HCl(aq) + NH3(aq) ) → NH4Cl(aq)
If 2 moles of NH3 are reacted then 2 moles of HCl must also be present since 1 HCl reacts with 1 NH3 from the balanced reaction.
c.) 2HCl(aq) + Ca(OH)2(s) → CaCl2(aq) + 2H2O(ℓ)
We can see that 2 HCl react with 1 Ca(OH)2, hence if 0.1 mol of Ca(OH)2 is reacted then 0.2 mol HCl must also be present.
N the nucleus, there are protons and neutrons. That's two parts.
<span>Outside the nucleus, there are electrons. That's a total of three parts and that is all that chemists discuss. Theoretical physicists talk about other sub nuclear "parts", but if you include them, the number goes way over 5. </span>
<span>The "shells", "sub-shells", "orbits", "orbitals", "probabilities" and the like are not physical parts, but only descriptions of energy</span>
