Answer:
See below, please
Explanation:
Because the mole ratio
Now, at the beginning
Mole m(CH4) =4 mol, m(O2) = 5 mol
If O2 gas is fully reacted, used up,
Need m(CH4) = 2.5 mol
Hence, the mole of CH4 left
m(CH4) = 4-2.5=1.5 mol
That means
At the end of the reaction,
m(CH4) =1.5 mol
m(O2) = 0 mol
Answer:
a) Higher than −34 °C because dispersion forces are stronger in iodine due to a greater number of electrons.
Explanation:
Both chlorine and Iodine are halogens. They belong to the 7th group on the periodic table.
To examine the trend of boiling point in this group we must consider the nature of the intermolecular bonds that would be formed by the molecules of these elements. We know that London dispersion forces, a type of van der Waals attraction would be more prevalent. This is so because the molecules here would be non-polar and the uneven distribution of the constantly moving electrons would initiate the intermolecular bonding.
The uneven charge distribution leads to the formation of a temporary dipole.
This makes boiling point increase down the group because more electrons becomes involved and the bond becomes stronger.
Answer:
3N2Cl4 + 3CH4--> 3CCl4 + 3N2 + 6H2
This simplifies to:
N2Cl4 + CH4 --> CCl4 + N2 + 2H2
A. Sedimentary rock. This is because sedimentary rock contains sediments and sometimes some fossils.
Answer:
Neutral.
Explanation:
Protons have a positive charge. In this problem there are 12.
Electrons have a negative charge. In this problem there are 12.
Neutrons have a neutral charge that isn't relevant tot the overall charge, it can be ignored.
#protons - #e- = charge
12 - 12 = 0
The protons and electrons balance each other out, resulting in a 0 net charge. This means the atom has a neutral charge.