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3 years ago

What is the probability of picking a Jack or a Queen?

Mathematics

2 answers:

Lesechka [4]3 years ago

8 0

8/52 we say that the probability of choosing a queen or jack in a pack of 52 cards is 8 / 52.

Rama09 [41]3 years ago

6 0

Answer:

8/52

Step-by-step explanation:

There are 4 Jacks and 4 Queens in a deck of 52 cards, bumping the odds up to 8/52.

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An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

sattari [20]

They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:

y=150-600t x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)

7 0

3 years ago

I need help on this questions #4 and #5

11Alexandr11 [23.1K]

4) 5x+8= -27
5) a÷4+1.5=b

3 0

3 years ago

Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per mi

miss Akunina [59]

Answer:

Mean = 0, Standard deviation = 1

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 77.5 beats per minute

Standard Deviation, σ = 11.6 beats per minute

We are given that the distribution of pulse rates of women is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Putting the values, we get,

$z_{score} = \displaystyle\frac{x-77.5}{11.6}$

After, the standardization, that is conversion of all pulse rates of women to z scores, the mean of the distribution is 0 and standard deviation is 1.

Mean = 0, Standard deviation = 1

7 0

3 years ago

158÷37 show work need help

denis-greek [22]

Here’s a pic of my work, it shows that the numbers 2,7,0 repeat.

Hope this helps!! :)

8 0

3 years ago

If Joe drives 186.83 miles on a business trip, and the reimbursement from his company is $13.08. At what rate is Joe's employer

kirill115 [55]

Answer:

7 cents/mile

Step-by-step explanation:

You are looking for a unit rate of cents per mile.

Change the dollar amount to cents, and divide by the number of miles.

$13.08 * (100 cents)/$ = 1308 cents

(1308 cents)/(183 miles) = 7.001 cents/mile

8 0

3 years ago