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frez [133]
3 years ago
9

Solve for x please need help need answer ASAP

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

From the given diagram , in smaller triangle BCD , Using Pythagoras theorem we can write

x^2=p^2+4^2\\\\x^2=p^2+16\\\\

In Triangle ABD , we can write

q^2=21^2+p^2\\\\

In Triangle ABC

(21+4)^2=q^2+x^2\\\\q^2+x^2=625\\

Now using the above three equations we can write

21^2+p^2+x^2=625\\\\21^2+x^2-16+x^2=625, x^2=p^2+16\\\\2x^2+425=625\\\\2x^2=625-425\\\\2x^2=200\\\\x^2=100\\\\x=10\\

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To find the area of a parallelogram, multiply the base by the height.

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Step-by-step explanation:

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A store is having a sale in which all items are reduced by 20%. Including tax, Jennifer paid $21 for a pair of shorts. If the sa
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Answer: the original price of the shorts was $25

Step-by-step explanation:

Let x represent the original price of the shorts.

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Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3
vagabundo [1.1K]

Answer:

not

Step-by-step explanation:

\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=

First is A and Second is B

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\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]

b)

\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]  \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =

Now let's find B*A

\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]

c) They are not

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