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Over [174]
2 years ago
13

Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling C

Mathematics
1 answer:
katovenus [111]2 years ago
8 0

Answer:

2.75 x (c) = 500

Step-by-step explanation:

i think this is it

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Answer:

Can you explain to me what x is?

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Which of the ratios below is equivalent to 2:3? Select all that apply.
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Answer:B,C,E

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Maggie collected 63 pounds of paper for recycling. Carl collected 9 pounds. How many times as many did Maggie collect as Carl
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Read 2 more answers
Let II be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). Let S, x² + y^2 + z = 4 be another
stealth61 [152]

Let F(x,y,z)=f(x,y)-z. The tangent plane to f(x,y) at (1, 2, -6) has equation

\nabla F(1,2,-6)\cdot(x-1,y-2,z+6)=0

We have

\nabla F(x,y,z)=(-4x,-6y,-1)\implies\nabla F(1,2,-6)=(-4,-12,-1)

Then the tangent plane has equation

(-4,-12,-1)\cdot(x-1,y-2,z+6)=0\implies -4(x-1)-12(y-2)-(z+6)=0\implies 4x+12y+z=22

Let g(x,y)=4-x^2-y^2, and G(x,y,z)=g(x,y)-z. The tangent plane to S at a point (a,b,c) is

\nabla G(a,b,c)\cdot(x-a,y-b,z-c)=0

We have

\nabla G(x,y,z)=(-2x,-2y,-1)\implies \nabla G(a,b,c)=(-2a,-2b,-1)

so that this plane has equation

(-2a,-2b,-1)\cdot(x-a,y-b,z-c)=0\implies2ax+2by+z=2a^2+2b^2+c

In order for this plane to be parallel to the previous plane, we need to have

\begin{cases}2a=4\\2b=12\end{cases}\implies a=2,b=6\implies g(a,b)=c=-36

so the point we're looking for is (2, 6, -36).

6 0
3 years ago
Which expressions are equivalent to 2 (three-fourths x 7) minus 3 (one-half x minus 5)? Check all that apply. -1 29 2 (three-fou
zloy xaker [14]

The expression is equivalent to \rm 2(\dfrac{3}{4}x ) + 2(7) + (-3) ( \dfrac{1}{2}x) + (-3) (-5).

<h2>Given that</h2>

Expression; 2 \left ( \dfrac{3}{4}x+7 \right ) -3 \left ( \dfrac{1}{2}x - 5 \right )

<h3>We have to determine</h3>

Which expressions are equivalent to the given expression.

<h3>According to the question</h3>

Expression; 2 \left ( \dfrac{3}{4}x+7 \right ) -3 \left ( \dfrac{1}{2}x - 5 \right )

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

\rm a(b+c) = ab +ac

Then,

The equivalent expression is,

= 2 \left ( \dfrac{3}{4}x+7 \right ) -3 \left ( \dfrac{1}{2}x - 5 \right )\\&#10;\\&#10;=  ( 2 \times \dfrac{3}{4}x) + ( 2\times 7 ) -(3 \times  \dfrac{1}{2}x)-( 3 \times  - 5 )\\&#10;\\&#10;= 2(\dfrac{3}{4}x ) + 2(7) + (-3) ( \dfrac{1}{2}x) + (-3) (-5)

Hence, the expression is equivalent to \rm 2(\dfrac{3}{4}x ) + 2(7) + (-3) ( \dfrac{1}{2}x) + (-3) (-5).

To know more about Equation click the link given below.

brainly.com/question/13174611

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