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Oliga [24]
3 years ago
14

This is an example of an arithmetic series: 6 + 8 + 10 + 12 + . . . + (4 + 2n) + . . .

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

True. A series is arithmetic if its terms come from an arithmetic sequence.

And a sequence is said to be arithmetic any of its two consecutive terms differ by a fixed difference, common to any consecutive pair.

As you can see, in this case, all terms differ by 2, so the sequence

6,\ 8,\ 10,\ 12,\ \ldots,\ 4+2n

is arithmetic, and thus the series

6 + 8 + 10 + 12 + \ldots + (4+2n)

is arithmetic as well.

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Need help with this one also
-Dominant- [34]

Answer:

D

Step-by-step explanation:

10/7 = 1.4285

9/y = 1.4285

Multiply both sides by y.

9 = 1.4285y

Divide both sides by y.

6.3 = y

6 0
3 years ago
Maya collected data about the number of ice cubes and milliliters of juice in several glasses of juice and organized the data in
Alex_Xolod [135]

Answer: B. 89

Step-by-step explanation:

-29.202x7= -204.414

-204.414+293.5= 89.086

So the answer is B. 89

5 0
3 years ago
In a standard deck of 52 playing cards, what is the probability
Deffense [45]

Answer:C

Step-by-step explanation:

6 0
3 years ago
Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.
andrezito [222]

The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

<h3>What is a perfect square?</h3>

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

(a ± b)^2 = a ^2 ± 2ab + b ^2

$x^2-6x=1

x^2-2*3x=1

then $2ab = 2 * 3*x = 2 * x *3

The value of a = x and b = 3

$b^2=3^2=9

$x^2-6x+9=1+9

$x^2-6x+9=10

The value added to the equation $x^2-6x=1 exists $x^2-6x+9=10.

To learn more about perfect square refer to: brainly.com/question/6946048

#SPJ4

3 0
2 years ago
PLEASE HELP
Alecsey [184]

Answer:

B I think

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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