To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
Answer:
x^2 - 2xy + y^2.
Step-by-step explanation:
(x - y)^2
= (x - y)(x - y)
= x(x -y) - y(x - y)
= x^2 - xy - xy + y^2
= x^2 - 2xy + y^2.
Y² + 10z - 10y - yz = (y - 10)(y - z)
You do 2x20 which is basically 2x2 (4) add a zero and your answer is 40
Answer:
3/4
Step-by-step explanation:
We need two points to find the slope
( 20,20) and (60,50)
m = (y2-y1)/(x2-x1)
= (50-20)/(60-20)
= 30/40
= 3/4
