Given that , we have
, so that
Take the derivative and find the critical points of :
Take the second derivative and evaluate it at the critical point:
Since is positive for all
, the critical point is a minimum.
At the critical point, we get the minimum value .
Answer:
The solution of the given equations
x =4 , y = 1
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step(l</u>):-
Given the system of equations -5x+13y = -7 ..(l)
5x+4y=24 ..(ll)
<u>Step(ll)</u>
Adding (l) and (ll) equations and cancelling '5x' terms we get
13y+4y = -7 +24
17y = 17
dividing '17' on both sides, we get
y=1
<u>Step(lll):-</u>
Substitute y=1 in equation (l) , we get
-5x+13y = -7
-5x + 13(1) = -7
subtracting '13' on both sides, we get
-5x +13 -13= -7 -13
-5x = -20
Dividing '-5' on both sides, we get
x = 4
<u>Conclusion</u>:-
The solution of the given equations
x =4 , y = 1