10. Which expression is represented by the model below?<br> +<br> o

And English class has read the first 384 pages of your novel. If this is 75% of the entire book, how many total pages are in the

Doss [256]

384 pages (0.75) = 288 pages
Add this to the original amount of pages.

384 + 288 = 672 total pages.

3 0

3 years ago

Read 2 more answers

Can anyone plzzzz help me with this question of linear equation in two varaiable plzzzzzz... Its very important... Plz solve it

kotegsom [21]

That's not a linear system, but you have an awesome school system for giving you this problem.

$\dfrac 5 y - \dfrac 2 x = \dfrac{13}6$

Multiply by 6xy to clear the fractions.

$30x - 12y = 13 xy$

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.

$30x = y(13 x +12)$

$y = \dfrac{30x}{13 x + 12}$

Let's clear the fractions from the second equation, multiplying out common denominator xy:

$\dfrac {36} x - \dfrac {24} y = 1$

$36y - 24 x = xy$

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

$36 \left( \dfrac{30x}{13 x + 12} \right) - 24 x = x \left( \dfrac{30x}{13 x + 12} \right)$

$36(30x) -24 x(13x + 12) = 30x^2$

$1080 x - 312 x^2- 288 x = 30x^2$

$x(792 - 342 x)= 0$

$x = 0 \textrm{ or } x=792/342 = \dfrac{44}{19}$

We have to rule out x=0 because it's in the denominator.

$y = \dfrac{30x}{13 x + 12} = \dfrac{30(44/19)}{13(44/19)+12}$

$y = \dfrac{33}{20}$

Answer: (44/19, 33/20)

8 0

3 years ago

For a project, Gabrielle made a model of an Egyptian pyramid. The square base has a side length measuring 10 inches. The pyramid

Varvara68 [4.7K]

The pyramid is shown in the diagram below.
The pyramid is built from four congruent triangles and one square as the base

We have the side of the square, so the area is = 10×10 = 100

We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.

Using the Pythagoras rule
Height of triangle = $\sqrt{12^{2}+ 5^{2} } =13$

Area of one triangle = 1/2×10×12=60
Surface area of the pyramid = 100 + (4×60) = 340 square inches