Multiply out <span>f(x)=(x-8)(x-2): f(x) = x^2 - 8x - 2x + 16, or f(x) = 1x^2 - 10x + 16.
Thus, a=1, b= -10 and c=16.
One of several ways to find the vertex involves "completing the square."
x^2 - 10x + 16 = x^2 - 10x + 25 - 25 + 16, or y = (x-5)^2 -9, or y+9=(x-5)^2.
Compare this result to y-k = a(x-h)^2. We see that h=5 and k=-9.
Thus, the vertex is at (h,k) = (5, -9). </span>
Answer:
you substitue 8 for x then you sovle it like a normal equations
Step-by-step explanation:
thanks for points :D
Answer:
The answer is $22.80
Step-by-step explanation:
<h3><u>Given</u>:</h3>
Ahmad sells beaded neckless each large necklace sells for $6.10 and each small necklace sells for $4.50.
If Ahmad will sell 3 large necklaces and 1 small necklace then,
3 × $6.10 = $18.30
So, $18.30 + $4.50 = $22.8
Thus, If Ahmad will sell 3 large necklaces and 1 small necklace then he will earn $22.80.
<u>-TheUnknownScientist</u><u> 72</u>
when given the function f x 3x + 6 + f g x + 12 - 3 you have to find the values of M you want to play 3 m - 7 m squared minus one and then subtract that in after subtracting divide and that's so on and so on
With the Fibonacci Sequence, we keep adding the 2 previous numbers
1
+1
=2
then
1
+2
=3
2 +
3
=5
And we can continue
<span>
<span>
<span>
8
</span>
<span>
13
</span>
<span>
21
</span>
<span>
34
</span>
<span>
55
</span>
<span>
89
</span>
<span>
144
</span>
<span>
233
</span>
<span>
377
</span>
</span>
</span>
If we take a Fibonacci number and divide it by the PREVIOUS Fibonacci number (For example 377 / 233) we get:
<span>
<span>
<span>
1.61802575107296
</span>
</span>
</span>
This is something known as the phi ratio, which equals (1 + sq root(5)) / 2
or
<span>
<span>
<span>
1.6180339887499</span></span></span>
The further we carry out the Fibonacci sequence, the closer the division of (Fibonnaci Number "n") /(Fibonnaci Number "n-1") gets to be
(1 + sq root(5)) / 2
So, I would say that F52 / F51 would <span><span><span>equal 1.6180339887499 or be very close to it.
Look up the "Golden Ratio" in wkipedia
</span></span></span>
