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sesenic [268]
3 years ago
13

I need help with this question please!!!

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

Step-by-step explanation:

Each point of function b(x) is shifted by rule

x -----> ( x - 2 )

and

y -----> (y + 3)

( - 1.5, 0) ------> (- 3.5, 3)

(- 1, - 1) -----> ( - 3, 2)

(0, - 2) ------> ( - 2, 1)

(1, - 1) -----> ( - 1, 2)

(2, 3) -----> (0, 6)

(4, 7) -----> (2, 10)

......

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Zared plays basketball on his high school team. One of the things he needs to practice is his free throws. On his first shot, th
Marat540 [252]

Answer:

lol brainliest

Step-by-step explanation:

8 0
2 years ago
Nemo and Dory are meeting Crush at the tide pool. Nemo must swim 6 ¾ miles while Dory must swim 4 1/2 miles to reach their desti
gayaneshka [121]

Answer:

1.5 times.

Step-by-step explanation:

6.75 / 4.5 = 1.5.

5 0
3 years ago
John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho
Margarita [4]

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as ^4C_1.

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

=\ ^2C_1 \times ^4C_1\\\\=\ 8

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

8 0
2 years ago
Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and
mariarad [96]

9514 1404 393

Answer:

  1. (a, b, c, d) = (1, -4, 1, -2)
  2. (a, b, c, d) = (1, -4, 1, 2)
  3. (a, b, c, d) = (1, -4, 2, 6)

Step-by-step explanation:

Once you remove the common factor from the terms, you are looking for factors of the remaining constant term that have a sum equal to the coefficient of the linear term. These factors are the constants in the binomial factors.

__

1. 8 = (-4)(-2)   ⇒   x^2 -6x +8 = (x -4)(x -2)

  (a, b, c, d) = (1, -4, 1, -2)

__

2. -8 = (-4)(+2)   ⇒   3x^3 -6x^2 -24x = 3x(x -4)(x +2)

  (a, b, c, d) = (1, -4, 1, 2)

__

3. -12 = (-4)(3)   ⇒   2x^2 -2x -24 = 2(x -4)(x +3) = (x -4)(2x +6)

   (a, b, c, d) = (1, -4, 2, 6)  or  (2, -8, 1, 3)

3 0
3 years ago
What is the midpoint of a segment whose endpoint are (-3,-3) and (-13,-13)
oksian1 [2.3K]
<span>(((-3) + (-13)) / 2, ((-3) + (-13)) / 2) </span>
<span>= (-16 / 2, -16 / 2) </span>
<span>= (-8, -8) 

1 = D</span>
5 0
3 years ago
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