So we want to solve like if it was just a basic equation. We start with 25+3.50x<17+7.50x and get rid of our smallest x. That means we get rid of the 3.50x by subtracting from both sides and our new equation is 25<17+4x. Let’s get our x by itself shall we, so let’s subtract 17 from both sides and we get 8<4x. Finally all we do is divide by 4 and just like that 2
B is the answer
just like the picture
( T' is not exact. it just shows the reflection)
Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
Answer:
x times (x+1).
If it's wrong, then I'm an idiot.
Step-by-step explanation:
Answer:
y = 6.50x + 6 or 71 = 6.50x + 6
10 people are the max you can invite
Step-by-step explanation:
We have the simple equation
y = 6.50x + 6
6.50x because it it per person
6 because it is a flat one time charge
We want the max to be 71 so that will be our y
71 = 6.50x + 6
We are now going to solve for x
65 = 6.5x
x = 10
Hope it helps! (:
