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lilavasa [31]
2 years ago
14

I cannot find the answer to this question please help

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0
The answer would be 689
You might be interested in
62 62 65 65 115 115 118 118<br> I have no idea how to solve this, will give brainliest
Kobotan [32]

Answer:

1.ABC = 45°,DBE = 45°.  ABD = 135°,CBE = 135°

2.ABC = 62°, DBE = 62°, ABD =118°,CBE = 118°

Step-by-step explanation:

1.angle ABC = angle DBE because they are vertical.  You can write the equation 3x+38 = 5x+20 and find both angles.  When you solve, x=9.  You substitute it in.  ABD is equal to 180-45° because it is supplementary with ABC. ABD = CBE b/c vertical angles.

2.You do the same thing.  4x+2=5x-13,x=15.  You substitute in 15 for x and get 62°.  They are the equal angles.  For ABD you do 180 -62 since they are supplementary angles, which gets you 118 which applies for both because they are vertical angles.

I want the brainliest.

8 0
2 years ago
I need help please! :x:
zavuch27 [327]

Answer:

Charge(x) = $60 + ($0.75/mile)x, where x is the number of miles driven.

Step-by-step explanation:

That $60 is the y-intercept and represents the (flat) charge per session.  The  ($0.75/mile)x represents the amount charged for the total number of miles driven.

4 0
3 years ago
Can to answer all 4 please?
Tasya [4]
1) A - yes, b - no, c -  yes
2) false, true, false
3) 85p - 34%
      xp - 66%
x = 165 - she has to read 165 more pages.
4) Sylvia earns 84/12 = 7$/hr
maximum she can earn is 7*15 = 105 $
she will earn 105$ if she works for 15 hours
5 0
2 years ago
What is the value of -2(5) + 3?
pantera1 [17]
Answer is -7

-2(5)+3
-10+3
-7

Hope it helps
4 0
3 years ago
Read 2 more answers
Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.
Vladimir [108]
\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt
\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k

Given \mathbf r(1)=\mathbf i+\mathbf j, we have

\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12

so that the particular solution is

\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k
8 0
3 years ago
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