A point on the graph (for train b) that is exact is (2,250). From the origin, the rise is 250 and the run is 2. Rise/run would give us 250/2, which is 125. This means that train B travels 125mi every hour. For train A, we subtract the distance from hour 2 from hour 3 to get the miles per hour (because 3-2=1, subtracting the distance of hour 3 from 2 will give us the distance in 1 hour). 180-120= 60, meaning train A travels at 60mph. 60<125, meaning A
Answer:
The highest speed measured was 78.2 Mbps.
n = 50
a)What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
= 78.2 - 18.22
=59.98
b)How many standard deviations is that [the difference found in part (a)]
=
c) Convert the carrier's highest data speed to a z score.
d) If we consider data speeds that convert to z scores between minus2 and 2 to be neither significantly low nor significantly high
Yes the carrier's highest data speed is significant because it is greater than 2.
is the difference.
What is an expression?
⇒ An expression is a combination of numbers, variables, and functions (such as addition, subtraction, multiplication or division, etc.)
Calculation :
⇒
⇒
⇒1/(x-2) [(3x²-5x{x-5})/(x-5)]
⇒1/(x-2) [(3x²-5x²+25x)/(x-5)]
⇒1/(x-2) [ (-2x²+25x)/(x-5)]
⇒
at x=2 and x=5 the denominator becomes zero If the denominator of a fraction is zero, the expression is not a legal fraction because its overall value is undefined.
⇒ is the difference
learn more about similar expressions here :
brainly.com/question/16850029
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Hello!
First of all, we can subtract the stretching time. This gives us 20. If we divide by the four laps we get 5 minutes per lap.
Now, one lap is 400 meters (most tracks are), which is equal to 15,748.03 inches. This means it takes her five minutes to walk 15,748.03 inches. This is also equal to 300 seconds, so it takes her 300 minutes per 15,748.03 inches.
But if we round our big inches number to the nearest ten thousandth, we get 16,000, so in a simpler form her pace is 300/16,000. But we need to find in per second. Therefore we will divide by 300 to find how many inches she walks per second. This means she walks about 53.33 inches per second.
I hope this helps!