Question

Find the inverse of square root f(n) = n – 3.

Answer 1

Answer:

$f'(n) = n + 3$

Step-by-step explanation:

Given

$f(n) = n - 3$

Required

The inverse

$f(n) = n - 3$

Replace f(n) with y

$y = n - 3$

Swap positions of y and n

$n = y - 3$

Make y the subject

$y = n + 3$

Replace y with f'(n)

$f'(n) = n + 3$