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Art [367]
3 years ago
15

Help help help on marhswatch please help!!

Mathematics
1 answer:
Savatey [412]3 years ago
6 0

7x-35<2x-10 distribut it

7x-2x<-10+35 collect like them

5x<25 divide both side by 5

x<5

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What does common factors mean?
bearhunter [10]
Factors are the numbers you multiply together to get another number. when you find the factors of two or more numbers, and then find some of the numbers (factors) are the same (common) you have common factors.

example: 12 and 36

12: 1x12, 2x6, 3x4
36: 1x36, 2x18, 3x12, 4x9, 6x6

the common factors in these numbers are 1, 2, 3, 4, 6 and 12

hope this helped you out!
6 0
3 years ago
100 points !!!!!!!!!!!!! please help
m_a_m_a [10]

We have to,

write a word problem for this equation,

→ 2/3 × 5

Let's write a word problem,

<u>For one student 2/3 part of one cake is needed. Then how </u><u>many</u><u> </u><u>cakes will they have to buy for 5 students?</u>

5 0
3 years ago
Read 2 more answers
Please help me answer
suter [353]

Answer:

The answer is indeed with Right angles

4 0
2 years ago
An octagonal pyramid ... how many faces does it have, how many vertices and how many edges? A triangular prism ... how many face
nadezda [96]

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

4 0
3 years ago
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
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