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lys-0071 [83]
3 years ago
12

In the kite shown, m

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0
Where is the rest of the problem?
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6 0
2 years ago
Find the equation of the line through (8,−6) which is perpendicular to the line y=x3−7.
ycow [4]

Answer:

y = (-1/3)(x + 10)

Step-by-step explanation:

The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3.  Thus, the perpendicular line has the slope -1/3.

Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:

y = mx + b    =>    -6 = (-1/3)(8) + b, or

-6 = -8/3 + b.  We must solve for the y-intercept, b:

Multiplying all three terms by 3 removes the fraction:

-18 = -8 + 3b.  Thus, -10 = 3b, and so b must be -10/3.

The desired equation is    

y = (-1/3)x - 10/3, or

y = (-1/3)(x + 10)

8 0
3 years ago
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