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kramer
2 years ago
13

A)ab b)bh c)gc d)fe help me please

Mathematics
2 answers:
mamaluj [8]2 years ago
6 0

Answer:

Its a

Step-by-step explanation:

Svet_ta [14]2 years ago
5 0

Answer:

Letter C)  bh

Step-by-step explanation:

Segment bh is straight across cd and parallel line extend in the same direction but never intersect.

Hope this helps

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Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the
ludmilkaskok [199]
By Stokes' theorem,

\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S

where \mathcal C is the circular boundary of the hemisphere \mathcal M in the y-z plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle

where 0\le t\le2\pi. Then the line integral is

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt
=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi

We can check this result by evaluating the equivalent surface integral. We have

\nabla\times\mathbf f=\langle1,0,0\rangle

and we can parameterize \mathcal M by

\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle

so that

\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv

where 0\le v\le\dfrac\pi2 and 0\le u\le2\pi. Then,

\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi

as expected.
7 0
3 years ago
TC= 0.0001Q^2-0.02Q+5+500Q
Leona [35]

Answer:   0

.

0

0

0

1

2

−

0

.

0

2

+

5

+

5

0

0

Step-by-step explanation:

5 0
2 years ago
A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med
Troyanec [42]
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
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The probability of someone picked at random has cancer given that test result indicates cancer is  \frac{0.0396}{0.0396+0.0096}= \frac{33}{41}

The probability of someone picked at random has cancer given that test result indicates no cancer is \frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}

7 0
3 years ago
Which value of a in the exponential function below would cause the function to stretch?
maxonik [38]

Answer:

“1.5”

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
R + 12 = 86<br> what does r equal ?
AVprozaik [17]

86 - 12 = 74

74 + 12 = 86

5 0
3 years ago
Read 2 more answers
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