Question

Quadratic formula y=-0.005x^2+0.41x-5.1

Answer 1

A quadratic equation has the general formula expressed as:

ax^2 + bx - c = 0

This equation can be solved by the quadratic formula which is expressed as:

x = ( -b (+ or -) √(b^2 - 4ac) / 2a

From the given equation,  y=-0.005x^2+0.41x-5.1

a = -0.005
b = 0.41
c = -5.1

Using the quadratic formula and the corresponding values of the coefficient, we substitute these and obtain:

x = ( -b (+ or -) √(b^2 - 4ac) / 2a
x = ( -0.41 (+ or -) √(0.41^2 - 4(-0.005)(5.1)) / 2(-0.005)
x1 =66.71
x2 = 15.29

Therefore, the quadratic equation would be factored by using the values of x we obtained as follows:
y= -0.005x^2 + 0.41x - 5.1
y = (x - 66.71) ( x - 15.29 )