We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3
the solutions are
x=√2+3
x=-√2+3
The times plus method.... is where a mixed number.... for example, to get the improper fraction of 3 1/4, you multiply 4 and three, and add that number with 1. (try writing it on a piece of paper, times between the whole number and denominator, and a plus between the whole number and the numerator.) anyway we are going to use the reverse for this.
SO the numerator is 17, and 17 is divisible by 5..... 3 times (u get where I'm going??) and there's 2 left over so...... the answer for that one should be 3 2/5
Since 3 x 5= 15+2 is 17 ;)))
Moving ON for the one....pick like 15 or 16 to be the denominator.... and subtract the 15 or 16 from 17, and the number you get is your numerator...
The equation is y=mx+c
C=8
M=-1
Answer:
B)
x units
Step-by-step explanation:
Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:
Perimeter of a rectangle = 2 (l + b)
where: l is the length = 12 units and b is the breadth = 8 units. So that:
Perimeter of KMPT = 2 (12 + 8)
= 40 units
Dilating KMPT by a scale factor of
would create K'M'P'T' of dimensions;
× 12 units by
× 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.
Perimeter of K'M'P'T' = 2 (l + b)
= 2(9 + 6)
= 30 units
Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be
× perimeter of KMPT.
Therefore, if the perimeter of KMPT is x units, then;
perimeter of K'M'P'T' =
* x units
=
x units