The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:
Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
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The answer would be 11x-12
Answer:
140 routes
Total Number of roads from allen to dodge through baker and Carlson is 140 routes.
Step-by-step explanation:
Given;
Number of roads from Allen to baker = 5
Number of roads from baker to Carlson = 7
Number of roads from Carlson to dodge = 4
Total Number of routes from allen to dodge through baker and Carlson is;
N = 5×7×4
N = 140 routes
(x-h)²+(y-k)²=r² is the equation of a circle with radius of r
so if x-h=4 and y-k=3 then
4²+3²=r²
16+9=r²
25=r²
sqrt both sides
5=r
radius is 5 units
