I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:





In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]
Answer: OPTION A.
Step-by-step explanation:
You can observe that in the figure CDEF the vertices are:

And in the figure C'D'E'F' the vertices are:

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:
For C'(-8,-4) and C(-2,-1):

Let's choose another vertex. For E'(8,8) and E(2,2):

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.
Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:
→
Let no be x
Acc to ques
X + 2(1/x) = 3
X + 2/x = 3
X^2 + 2 = 3x
X^2 - 3x + 2 = 0
X^2 - x - 2x + 2 = 0
X (x-1) - 2 (x-1) = 0
(x-2) (x-1) = 0
X= 2 or x =1
If this answer was helpful then please mark it as the brianliest
Answer:
x=7/6
Step-by-step explanation:
x+2/4=5/3
-2/4 -2/4
x=5/3-2/4=7/6
3x-12+5-x=2x-7
2x-7 =2x-7
Means there are infinite solutions.