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ira [324]
2 years ago
11

What is an equation of the line that passes through the points (5,5) and (5, -8)?

Mathematics
1 answer:
Neporo4naja [7]2 years ago
6 0

Answer: x=5

Step-by-step explanation:

lol ill do this one too :))

bc i answered the other one with a step by step explanation and this one is the same other than numbers ill just leave that out

slope = y2 - y1 / x2 - x1

-8 - 5 / 5 - 5

-13 / 0

nothing can be divided by zero, so the slope is undefined

this means that the line will be vertical and not have the usual y = mx+b form

it'll be x = a formula

so bc the x value in both points is 5, we know that x = 5 is the equation of the line :))

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ICE Princess25 [194]

Answer:

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6 0
4 years ago
I NEED ALOT OF HELP SOMEONE!
DedPeter [7]
V = 1/3 * 3.14 * 11 * 6^2 = 414.48 m^3

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4 0
3 years ago
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weqwewe [10]

Answer:

b. g(x) = ƒ(3x)

Step-by-step explanation:

We can use the graph to find the transformation which has been performed to obtain g.

g(x) is more stretched than x which means the function values are multiplied by some integer to obtain g(x). <u>This eliminates the options a and d.</u>

Now to check which factor is used to transform the function f(x) we can divide the x-coordinates of the points of new and old function.

So,

6/2 = 3

-6/-2 = 3

The function is stretched by a factor of 3.

Hence, the correct answer is:

b. g(x) = ƒ(3x)  ..

6 0
3 years ago
PLZ HELP DUE AT 12
aleksandrvk [35]

Answer:

The first one would be m^30n^20p^30  

And the second one would be a^2 / d^4  

Step-by-step explanation:

For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.

For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4

Hope this helps :)

4 0
3 years ago
Two similar triangles are shown below: Which two sets of angles are corresponding angles? ∠w and ∠v; ∠x and ∠y ∠w and ∠y; ∠x and
VARVARA [1.3K]
I think the 2nd one I'm not really sure
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3 years ago
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