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3 years ago

f(x)=3/2x +4 Using the given function, plot all the ordered pairs for the values in the domain below {-8,-4,-2,0,2,4}

Mathematics

1 answer:

bagirrra123 [75]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 9x2 y2 and the p

dolphi86 [110]

The vector function is, r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.

First surface is the paraboloid, $z=9x^2+y^2$

Second equation is of the parabolic cylinder, $y=2x^2$

Now to find the intersection of these surfaces, we change these equations into its parametrical representations.

Let x = t

Then, from the equation of parabolic cylinder, $y=2t^2$ .

Now substituting x and y into the equation of the paraboloid, we get,

$z=9t^2+(2t^2)^2 = 9t^2+4t^4$

Now the vector function, r(t) = <x, y, z>

So r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Learn more about vector functions at brainly.com/question/28479805

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The square root of -108 minus the square root of -3

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square root(-108) - square root(-3) =8.66025404 i

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3 years ago

How do u work this problem out

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Andre ran 1/2 of a mile in 1/15 of an hour.

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Read 2 more answers

ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help

anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

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2 years ago