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iogann1982 [59]
3 years ago
15

4y-3(5y-2)=-4-4(-2-y)

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

-0.4

Step-by-step explanation:

luda_lava [24]3 years ago
7 0
Answer : y=2/15 or 0.13
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you got a new credit card with an interest rate of 18% compounded monthly and no minimum payment. you go on a shopping spree and
just olya [345]
The total amount owed after 6 months will be found using the formula:
FV=P(1+r/100*n)^n
P=principle=$10000
r=rate=18%
n=terms=0.5


FV=10000(1+18/2*100)^0.5
FV=$10,440.30651
Thus the amount owed will be $10440.30651
7 0
4 years ago
Help me pleaseeee thank you sm
Leno4ka [110]

Answer:

The answer is A) 379.9

Step-by-step explanation:

3.14(11^2)

3.14*11^2

3.14*(11*11)

379.94 if rounded to the nearest tenth it would be 379.9

7 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
Could I get help on some algebra? I need the explanation to know how to do it. +45 points
Fiesta28 [93]

Answer:

C

Step-by-step explanation:

A is right, D is right because they are on the outside and on different sides, B is actually right since they are on the inside and on different sides, so that leaves c, so this has to be the wrong one because they are not both interior since 5 is on the outside and 6 is inside even if they are both on the same side

6 0
3 years ago
Adult tickets to a play cost $1.75 each and student tickets cost $1.25 each. Suppose there are twice as many student tickets sol
Arada [10]

Answer: 200 adult tickets and 400 student tickets were sold.

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of student tickets that were sold.

Adult tickets to a play cost $1.75 each and student tickets cost $1.25 each. If the income from the play was $850, the expression would be

1.75x + 1.25y = 850- - - - - - - - - -1

Suppose there are twice as many student tickets sold as adult tickets. This is expressed as

y = 2x

Substituting y = 2x into equation 1, it becomes

1.75x + 1.25 × 2x = 850

1.75x + 2.5x = 850

4.25x = 850

x = 850/4.25

x = 200

y = 2x = 2 × 200

y = 400

6 0
3 years ago
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