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neonofarm [45]
3 years ago
13

HELLPPPPP IDK WHAT TO DOOO

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

The formula can be written in the form ...

... T = (original temperature) + x·(change in temperature each minute)

The problem statement gives you the original temperature (21 °C) and tells you the temperature after 12 minutes. You have to use that information to figure out the change in temperature each minute.

The change in temperature in 12 minutes is (75 °C) - (21 °C) = 54 °C. That is the change in 12 minutes, so the change in 1 minute will be 1/12 of that:

... 54/12 = 4.5

Using this value in the equation for T, we have

... T = 21 + 4.5x

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The amount of money in a saving account after t years is represented by the function f(t)=3600(1.035)^t. What does the value 360
Olegator [25]

Answer: The amount of money that was in it originally

Step-by-step explanation:

3 0
2 years ago
A park is rectangular with a length of 1/2 miles. If the area of the park is 6/8 square miles, what is its width? Input your ans
Mademuasel [1]

Step-by-step explanation:

Area of Park = Length * Width

Therefore Width = Area / Length

= (6/8) / (1/2) = (6/8) * (2/1) = 3/2 miles.

8 0
3 years ago
Please help me will give branlist
MatroZZZ [7]

Answer: 36 hotdogs

Step-by-step explanation: You need to find the least common multiple of 9 and 12.

You can check by multiplying 9 and 12 by consecutive whole numbers until you find a number that they match.

Example:

9*1= 9 , 9*2=18, 9*3= 27, 9*4=36, 9*5=45

12*1=12, 12*2=24, 12*3 =36

They both share 36.

7 0
3 years ago
M is the midpoint of , cm = 2x + 3, and md = 3x – 6. what is cd? answer
wlad13 [49]
<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:

MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9

CM = 2x+3 = 2*9+3  18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42
7 0
3 years ago
Which quadratic equation has solutions x=8 and x=−1?
andrezito [222]
There are two ways you can do this

Using the formula


{x}^{2}  - (sum \: of \: roots)x + poduct \: of \: roots = 0

{x}^{2}  - (8+-1)x +  - 1 \times 8 = 0


{x}^{2}  - 7x  - 8 = 0


Working backwards


x = 8 \: or \: x =  - 1
\Rightarrow x-8=0  \: or  \: x+1=0

\Rightarrow (x-8)(x + 1)=0
\Rightarrow  {x}^{2}   + x -8x - 8 = 0
\Rightarrow  {x}^{2}  - 7x - 8 = 0
7 0
3 years ago
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