Answer:
see below
Step-by-step explanation:
y' = -2e⁻ˣcos(x) -sin(x)2e⁻ˣ +e⁻ˣsin(x)-cos(x)e⁻ˣ = e⁻ˣ(-2cos(x)-2sin(x)+sin(x) -cos(x))
=e⁻ˣ(-3cos(x)-sin(x))
y'' = -e⁻ˣ(-3cos(x)-sin(x)) + (3sin(x)-cos(x))e⁻ˣ
y'' = e⁻ˣ[3cos(x)+sin(x) + 3sin(x)-cos(x)] = e⁻ˣ[2cos(x)+4sin(x)]
y''+2y'+2y = 0
e⁻ˣ[2cos(x)+4sin(x)] + 2[e⁻ˣ(-3cosx-sinx)] + 2[2e⁻ˣ cos(x)−e⁻ˣ sin(x)]
e⁻ˣ[2cos(x)+4sin(x)-6cos(x)-2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[-4cos(x)+2sin(x)+4cos(x)-2sin(x)]
e⁻ˣ[0cos(x)+0sin(x)] = 0
Answer:
Step-by-step explanation:
Let x = degrees of the largest angle.
The smallest angle is two thirds the size of the largest, so the smallest angle is (2/3)x.
The middle angle is 4 degrees less than the largest, so it is x - 4.
The largest angle is of course x.
So add all three angles to equal the total degrees, which you have not provided. If you do have it and just forgot to post it, here is the formula:
(2/3)x + (x - 4) + x = ?
(8/3)x - 4 = ?
(8/3)x = ? + 4
x = (3/8)? + 1.5
Maximum number of packets = 8
16 ÷ 8 = 2
There are 2 pencils in each packet.
24÷8 = 3
There are 3 erasers in each bag.
Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
