Given that 4000 items are checked in one month, let the number of detective items be represented as y.
Quality control finds on average that 0.026% of the items in the factory are detective. This implies that
![\text{Number of }\det ective\text{ items = }\frac{\text{0.026}}{100}\times\text{Total number of items checked}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20%7D%5Cdet%20ective%5Ctext%7B%20items%20%3D%20%7D%5Cfrac%7B%5Ctext%7B0.026%7D%7D%7B100%7D%5Ctimes%5Ctext%7BTotal%20number%20of%20items%20checked%7D)
When 4000 items are checked, we have the number of detective items to be evaluated as
![\begin{gathered} \text{Number of }\det ective\text{ items = }\frac{\text{0.026}}{100}\times\text{Total number of items checked} \\ y=\frac{0.026}{100}\times4000 \\ \Rightarrow y=1.04 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BNumber%20of%20%7D%5Cdet%20ective%5Ctext%7B%20items%20%3D%20%7D%5Cfrac%7B%5Ctext%7B0.026%7D%7D%7B100%7D%5Ctimes%5Ctext%7BTotal%20number%20of%20items%20checked%7D%20%5C%5C%20y%3D%5Cfrac%7B0.026%7D%7B100%7D%5Ctimes4000%20%5C%5C%20%5CRightarrow%20y%3D1.04%20%5Cend%7Bgathered%7D)
Hence, the number of detective items is 1.04.
Split the second term in 6x^2 + 17x + 5 into two terms
6x^2 + 15x + 2x + 5 = 0
Factor out common terms in the first two terms, then in the last two terms.
3x(2x + 5) + (2x + 5) = 0
Factor out the common term 2x + 5
(2x + 5)(3x + 1) = 0
Solve for x
<u>x = -5/2, -1/3</u>
The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).
Here, b = 18 cm and h = 9 cm. Thus, the desired area is:
(18 cm)(9 cm)
A = ----------------------- = 81 cm^2
2
This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.
Answer:
![\angle NRQ =85 \degree](https://tex.z-dn.net/?f=%20%5Cangle%20NRQ%20%3D85%20%5Cdegree)
Given:
![\angle RPQ = 45 \degree \\ \angle PQR = (6x + 4)\degree \\ \angle NRQ = (15x - 5)\degree](https://tex.z-dn.net/?f=%20%20%5Cangle%20RPQ%20%3D%2045%20%5Cdegree%20%5C%5C%20%20%5Cangle%20PQR%20%3D%20%286x%20%2B%204%29%5Cdegree%20%5C%5C%20%20%5Cangle%20NRQ%20%3D%20%2815x%20-%205%29%5Cdegree%20)
Step-by-step explanation:
Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>
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Answer:
The inequality should be written as $2.50 times c is greater than or equal to c.
Step-by-step explanation:
First, identify what you know:
1) Each chocolate bar is $2.50
2) Sebastian needs to raise at least $500
So, Sebastian needs to sell at least enough chocolate bars to hit $500. The inequality cannot be written as less than or equal to, because he can't sell less than the number of chocolate bars needed to make $500.
Automatically, I can calculate the minimum number of bars he'll need to sell.
500/2.50 = 200 chocolate bars minimum
c must equal greater than or equal to $500, for Sebastian to raise enough money! So, basically Sebastian has to sell 200 bars OR more.
Hope this helps! :)