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2 years ago

H(a) = 2a +4 g(a) = 4a + 2 Find (h+g)(a)

Mathematics

2 answers:

Alecsey [184]2 years ago

6 0

The answer needs to be right 8-4 a

hjlf2 years ago

3 0

Answer:

8−4 a

Step-by-step explanation:

x=g(h(a−4))

h(a−4)=−2(a−4)−5 = −2 a+8−5=3−2 a

Apply g.

g(h(a−4))=g(3−2a)=2(3-2a)+2=6−4a+2

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Use the table of values below to select the correct statement.

quester [9]

Answer:

Linear function with rate of change/growth = 2.5, which agrees with the fourth statement listed in the answers options.

Step-by-step explanation:

Notice that both columns of reported x and y values are increasing.

Then examine how the given x-values increase:

-2, 2, 6, 10, 14 (in steps of 4 units)

and how their corresponding y-values increase:

-2, 8, 18, 28, 38 (in steps of 10 units)

therefore, if we do the rate of change for any pair $(x_1,y_1)$ and $(x_2,y_2)$ , we get the following constant rate of change:

$\frac{y_2-y_1}{x_2-x_1} = \frac{10}{4} =2.5$

Given that this relationship is valid for any pair of (x,y) values. we conclude that the rate of increase is constant, and therefore we are in the presence of a linear function, whose rate of change is 2.5

8 0

2 years ago

What is an equation of the line that passes through the points (2,5) and

harkovskaia [24]

Y-5=-1/2(X-2)
the simplified version of this equation (so you can plug into a calculator) is
Y=-1/2x+6

3 0

2 years ago

Christine purchased a prepaid phone card for $20. Long distance calls cost 18 cents a minute using this card. Christine used her

Luda [366]

Answer:

4 minutes and 32 seconds

Step-by-step explanation:

card $20.00-money left over $15.68 $20.00-$15.68 4.32

6 0

2 years ago

6a squared - 15a - 8a + 20

Sav [38]

Heya!

Here is your answer:

6a²-15a-8a+20

= 3a(2a-5) -4(2a-5)

= (3a-4)(2a-5)

:)

4 0

2 years ago

Read 2 more answers

p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.

Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

$\frac{p}{q {r}^{2} } = k$

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

$\frac{200}{2(3) {}^{2} } = k$

$\frac{200}{18} = k$

$\frac{100}{9} = k$

Now, since we know our constant, let find p.

$\frac{p}{q {r}^{2} } = \frac{100}{9}$

Q is 5, and r is 2.

$\frac{p}{5( {2}^{2}) } = \frac{100}{9}$

$\frac{p}{20} = \frac{100}{9}$

$p = \frac{2000}{9}$

3 0

1 year ago