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2 years ago

6

quadritlateral with two separate pairs of equal sides and my four sides cannot be equal, my equal sides are next to each other.

What am

1 answer:

Anarel [89]2 years ago

3 0

Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.

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Fundamental Counting Principle (L1)

Gala2k [10]

9 and 14 are the answers

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2 years ago

Equipment was acquired at the beginning of the year at a cost of $465,000. the equipment was depreciated using the straight-line

Troyanec [42]

A. Using the straight-line depreciation method, we can calculate for the depreciation using the formula:

d = (P – S) / n

Where,

P = present value

S = salvage value

n = number of life years

Substituting the given values:

d = ($465,000 - $45,000) / 15

d = $28,000

The depreciation for the first year was $28,000 and the book value is $437,000.

B. Calculating for the book value at the end of eight year:

BV (8) = $465,000 – 8 * $28,000

BV (8) = $241,000

<span>Since the equipment was sold at only $235,000 therefore there was a loss of $6,000.</span>

<span>C. Chart of accounts is needed.</span>

7 0

3 years ago

Can the coeffitient of different terms be simplified fractions multiplication

zalisa [80]

No, it would only work with similar terms. However, you would be able to multiply them, like 2x times 2y = 4xy.

7 0

2 years ago

Please help (see picture)

Rainbow [258]

9 1/10 × 7 1/3 × 4 1/2 = 298.935

7 0

3 years ago

Consider the triangles shown. If mUTV < mUTS < mSTR, which statement is true?

Tresset [83]

Answer:

The true statement is UV < US < SR ⇒ 1st statement

Step-by-step explanation:

"I have added screenshot of the complete question as well as the

diagram"

* <u><em>Lets revise the hinge theorem</em></u>

- If two sides of one triangle are congruent to two sides of another

triangle, and the measure of the included angle between these two

sides of the first triangle is greater than the measure of the included

angle of the second triangle then the length of the third side of the

first triangle is longer than the length of the third side of the second

triangle

* <em>Lets solve the problem</em>

- The figure has three triangles have a common vertex T

- m∠UTV < m∠UTS < m∠STR

- <u><em>From the hinge theorem above</em></u>

∵ The side opposite to ∠UTV is VU

∵ The side opposite to ∠UTS is US

∵ The side opposite to ∠STR is SR

∵ m∠UTV < m∠UTS < m∠STR

∴ UV < US < SR

* The true statement is UV < US < SR

5 0

3 years ago