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lesya692 [45]
3 years ago
6

quadritlateral with two separate pairs of equal sides and my four sides cannot be equal, my equal sides are next to each other.

What am

Mathematics
1 answer:
Anarel [89]3 years ago
3 0
Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.

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Solve Sine inverse x +sine inverse 2x = π/3 <br> Please solve it faster..
LuckyWell [14K]
Arcsin x + arcsin 2x = π/3

arcsin 2x =  π/3 - arcsin x

sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)

2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)

2x = √3/2 . cos(arcsin x) - (1/2)x)

but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²)  - (1/2)x)

Reduce to same denominator:

(4x) = √3 .√(1-x²)  - (x)===>5x = √3 .√(1-x²)

Square both sides==> 25x²=3(1-x²)

28 x² = 3 & x² = 3/28 &  x =√(3/28)



3 0
3 years ago
Josh​ simplified 4x - 8x ÷ 2 and said the answer was -2x. What was josh's error? What should his answer have been?
Svetradugi [14.3K]

Answer:

see explanation

Step-by-step explanation:

Given

4x - 8x ÷ 2

Under the rules of PEMDAS , division must be performed before subtraction.

Hence

4x - 8x ÷ 2 = 4x - 4x ← dividing - 8x by 2, then

4x - 4x = 0 ← correct answer

6 0
3 years ago
Build a triangle is it possible to build 5,5,3
allochka39001 [22]
No because adding the two fives will give you a 10 and 10 is greater than 3
7 0
3 years ago
Iteration - Maths Question attached
Ivanshal [37]

Answer:

7.8

Step-by-step explanation:

First I will try 50. I got 127,550, so that was way too big.

Let me try a smaller number. How about 5. I got 155, so that was a bit too small.

Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.

How about 7. I got 399.

Let me try 8. I got 584! That's really close. It's just a little too big.

I tried 7.5, and got 485.624. So close! Just a little higher.

Putting in 7.8 yields <u>543.192!</u> That's our answer.

8 0
3 years ago
You are about to take the road test for your​ driver's license. You hear that only 38​% of candidates pass the test the first​ t
OLga [1]

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

  1.        Given:

                 first test:38%

                 second test:76%

    SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

7 0
3 years ago
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