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3 years ago

6

quadritlateral with two separate pairs of equal sides and my four sides cannot be equal, my equal sides are next to each other.

What am

1 answer:

Anarel [89]3 years ago

3 0

Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.

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240 is equal to w more than 369

poizon [28]

240=w+369

w = -129

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2 years ago

The main floor of Kinsey's home is 1,425 square feet. The upper level is 875 square feet with one unfinished bedroom that measur

kvv77 [185]

The reportable square footage for Kinsey's home = 2150square feet.

The main floor of Kinsey's home is 1,425 square feet.

The upper level is 875 square feet with one unfinished bedroom that measures 150 square feet.

The finished basement is 1,425 square feet with 7.5-foot ceilings.

That means the square footage of the upper floor plus the main floor (minus the unfinished laundry area).

Kinsey should report square feet (1425+875- 150)

= 2150square feet.

Hence, The reportable square footage for Kinsey's home = 2150square feet.

Learn more about square footage here brainly.com/question/25845997

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1 year ago

Stock valued at $49.50 decreases in value by 12% each year. How much will the stock be worth in 5 years? Round your answer to th

bearhunter [10]

Answer:

Step-by-step explanation:

f(5)=49.5(0.88)^5

f(5)=$26.12

6 0

3 years ago

Helen wrote the following facts to try to show that division by 0 results in 0. Explain her error.

earnstyle [38]

Helen should of put 0 first, because if you're gonna divide, you need to put the product first, then one of the factoes.

So instead it should be 0÷(-7)=0

3 0

3 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

so

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago