Using system of linear equations the distance at the fisherman and the bobbler meets ls 8 miles
Speed in still waters = 7 mph
Stream speed = 3 mph
Upstream speed of canoe = 7 - 3 = 4 mph
<em>Distance</em><em> </em><em>between</em><em> </em><em>fisherman</em><em> </em><em>and</em><em> </em><em>bobbler</em><em> </em><em>=</em><em> </em><em>14</em><em> </em><em>miles</em><em> </em>
Let seperation distance = d
Meeting distance = 14 - d
<u>using the relation</u> :
<em>Distance= (speed × time)</em>
canoe distance , <em>d = </em><em>4t</em><em> </em><em>-</em><em> </em><em>-</em><em> </em><em>-</em><em> </em><em>-</em><em> </em><em>(</em><em>1</em><em>)</em>
Noobler distance = <em>14 - d = 3t </em><em>-</em><em>-</em><em>-</em><em>-</em><em>(</em><em>2</em><em>)</em>
Equate (1) and (2)
d/4 = (14 - d)/3
3d = 4 (14 - d)
3d = 56 - 4d
7d = 56
d = 8 miles
Hence, the distance is 8 miles
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