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Alecsey [184]
2 years ago
5

Solve by factoring x^2-8x-20-0

Mathematics
2 answers:
agasfer [191]2 years ago
6 0

Answer:

(x-10)(x+2)

Step-by-step explanation:

Oksana_A [137]2 years ago
5 0
X^2-8x-20 and if you rewrite that it’s (x-10) (x+2)
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Find two natural numbers that are multiples of both 12 and 15​
Diano4ka-milaya [45]

Answer:

60 and 120

Step-by-step explanation:

The LCM of 12 and 15 is 60

The smallest natural number that would be a multiple of 12 and 15 would be 60.

To find the second number, all you do is multiply 60 by 2 and you get 120.

(60 * 2 = 120)

8 0
2 years ago
Read 2 more answers
If x2 = 30, what is the value of x? (5 points)
marshall27 [118]

Answer:

It's C.

Step-by-step explanation:

√(30) to the power of 2 is equal to 30.

6 0
3 years ago
Need help with this plz
madreJ [45]

Answer:

4. x = 16.8

5. x = 35.98

Step-by-step explanation:

For both triangles that you need to work on, use the trigonometric function which is tan and you are dividing opposite by adjacent for the answers.

For number 4, the equation you are setting up is tan 35 = x/24.  Multiply 24 on both sides to get the answer which is 16.8 for the x side.

For number 5, the equation you are setting up is tan 17 = 11/x.  As a result on your calculator, you should get 35.98 for the x side.

6 0
2 years ago
2/3,2/6,2/8 fractions in order from greatest to least
Pani-rosa [81]
2/3,2/6,2/8
23 is the greatest because it has larger pieces
2/6 is the second greatest because it is a little smaller than thirds
2/8 is the least because it has the smallest pieces
5 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

z^2=1\implies z=\pm1\implies x=y=\pm2

There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}

3 0
3 years ago
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