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nordsb [41]
3 years ago
15

What is the square root of pi?

Mathematics
1 answer:
qwelly [4]3 years ago
6 0

The square root of Pi is approximately 1.77245.

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Please please help I am stuck and idk I tried so many times.
zhuklara [117]

Answer:

58.8 in^2

Step-by-step explanation:

The area of triangle given two sides and included angle.

8 0
3 years ago
How do you do...<br> cos2x-sin2x=1-2sin2x
Bess [88]
sin (2 \alpha) =2\cdot sin  \alpha \cdot cos  \alpha \\cos(2 \alpha )=1-2sin^2  \alpha \\-------------------- \\cos2x-sin2x=1-2sin2x\\cos2x+sin2x=1\\1-2sin^2x+2sinx\cdot cosx=1\\-2sinx(sin x-cosx)=0\\ -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\\\\1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\\2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \  cos x \neq 0\\tanx=1\ \ \Leftrightarrow\ \ x_2= \frac{ \pi }{4} +k \pi \ \ and\ \ k\in I
3 0
3 years ago
ANSWERRRRR PLEASE!! ~~
olganol [36]

Answer:

.33 liters of water and 3 liters of flour

Step-by-step explanation:

Well you can see how 1 liter of water is 3 liters of flour since there's a point on the graph, and you can find the liters of flour by just doing 1/3

8 0
3 years ago
Read 2 more answers
Which equation represents the graph?
klio [65]
The second option.

That is because
y -3 = - \frac{1}{2}(x + 1) \\ (y -3)+3 = (- \frac{1}{2} x - \frac{1}{2}) + 3 \\ y = - \frac{1}{2}x + 2 \frac{1}{2}
6 0
3 years ago
Find the sum of the interior angle measures of the green polygon,
Radda [10]

Answer:

The sum of interior angles of given polygon is 900°

Step-by-step explanation:

A regular polygon is a n-sided figure with n sides and the length of all sides is same.

In the diagram, we have a polygon with 7 sides.

The formula given is used to calculate the sum of interior angles of a polygon

Sum\ of\ interior\ angles = (n-2)*180

Here n is the number of sides of polygon

In the given polygon

n = 7

So,

Sum = (7-2)*180 = 5*180 = 900

Hence,

The sum of interior angles of given polygon is 900°

7 0
3 years ago
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