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kotykmax [81]
2 years ago
10

Help please asap asap asap

Mathematics
1 answer:
EastWind [94]2 years ago
8 0

Answer:1.5

Step-by-step explanation:

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.<br> Please answer this correctly
solniwko [45]

Answer:

no

Step-by-step explanation:

The answer is no because Shelley doesn't have any knowledge on what she's picking. This means that she can't influence what she picks, so it isn't biased.

8 0
2 years ago
Of the 12 clients who had their hair cut at Reagan's salon last month, 3 had black hair. Considering this data, how many of the
Crank

Answer:

if it is 12:3 so you need to find 20:x

12/3 20/x= 20 is 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0
1 year ago
The difference of a number and 6 is -11. What is the number?
Citrus2011 [14]

Answer:

The number is 17

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use (&lt;, &gt;, =) to compare 2⁄3 and 3⁄4. A. None of the above B. 2⁄3 &gt; 3⁄4 C. 2⁄3 &lt; 3⁄4 D. 2⁄3 = 3⁄4
Vinvika [58]
C 3/4 >2/3 bc 3/4=.75 and 2/3 = .66
4 0
3 years ago
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