3 years ago

Can you please Help me solve 4c < 28

Mathematics

1 answer:

meriva3 years ago

3 0

Answer:

4c < 28

divide by 4 both sides

x < 7

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Which is the value of this expression when a=-2 and b=-3

Lerok [7]

Answer:

$\frac{729}{64}$

Step-by-step explanation:

The given expression is

$(\frac{3a^{-3}b^{2} }{2a^{-1} b^{0} } )^{2}$

Where $a=-2$ and $b=-3$ .

When we say "evaluate the expression" refers to replacing the given values in the expression. Then, we solve each power in the numerator and denominator. After that, we solve each product in the fraction. At the end, we apply the square power. As follows

$(\frac{3a^{-3}b^{2} }{2a^{-1} b^{0} } )^{2}=(\frac{3(-2)^{-3}(-3)^{2} }{2(-2)^{-1} (-3)^{0} } )^{2}=(\frac{3(\frac{1}{-8})(9)}{2(\frac{1}{-2} (1))} )^{2} =(\frac{-\frac{27}{8} }{-1} )^{2} =\frac{27^{2} }{8^{2} } =\frac{729}{64}$