Please help im confused

Mathematics

1 answer:

anzhelika [568]2 years ago

4 0

what are options so i can help

Step-by-step explanation:

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When you move a circle vertically, the number that is part of the yterm changes.

svetlana [45]

Answer:

Step-by-step explanation:

The general equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2. You seem to be referring to "the y-coordinate of the center of the circle," that is, h in (h, k).

Yes, if you move a circle vertically, the y-coordinate of the center changes.

It's unclear what you're asking for help with. Please try to be more specific next time.

3 0

3 years ago

Read 2 more answers

The graph of f(x) = 2x is shown on the grid. The graph of g(x) = ()x is the graph of f(x) = 2x reflected over the y-axis. Which

pshichka [43]

Answer:

$g(x)=-2x$

Step-by-step explanation:

A point reflected across the y-axis maintains its y-coordinate, but its x-coordinate switches signs. So, a positive x-coordinate becomes negative, and a negative x-coordinate becomes positive.

Let's take a few points from the original function, f(x). Remember, if we know the function, we can find the y-coordinate for any x-coordiante by simply plugging it into the function's equation.

Generally, $f(x)=2x$

So:

$f(0)=2(0)=0\\f(1)=2(1)=2\\f(2)=2(2)=4$

Leading us to have the plot points (0,0), (1,2) and (2,4).

To reflect this across the y-axis for the g(x) equation, we just need to turn the x-coordinates negative, resulting in a set of (0,0), (-1,2), and (-2,4).

Since we know this is a linear function (because there are no exponents in the equation), we can calculate the slope of this new set of points by using just 2 of them. The slope will give us our equation, because since (0,0) is a point on our line, we know that the y-intercept is zero.

$slope=\frac{(y_{2}-y_{1})}{(x_{2}-x_{1})} \\slope=\frac{(4-2)}{((-2)-(-1))} \\slope=\frac{2}{-1}\\slope=-2\\\\g(x)=-2(x)$