Question

PLEASE IF U KNOW ANSWER HELP ME I NEED IT IN NEXT 10 MINUTES

Answer 1

Answer:

x + 2y - 3 = 0

Step-by-step explanation:

Coordinates of the points P and Q are (-3, 0) and (0, 6) respectively.

Slope of PQ = (0- 6)/(-3 - 0) = - 6/-3 = 2

Slope of line perpendicular to PQ = - 1/2

Since, required line passes through point R(7, - 2) and is perpendicular to PQ.

Therefore, equation of line in point slope form is given as:

$y - (-2) = - \frac{1}{2} (x - 7) \\ \\ y + 2 = - \frac{1}{2} (x - 7) \\ \\2(y + 2) = - (x - 7) \\ \\ 2y + 4 = - x + 7 \\ \\ 2y + 4 + x - 7 = 0 \\ \\ x + 2y - 3 = 0$

Therefore x + 2y - 3 = 0 is the required equation of line.

Answer 2

Answer:

Answer:

x + 2y - 3 = 0

Step-by-step explanation:

Coordinates of the points P and Q are (-3, 0) and (0, 6) respectively.

Slope of PQ = (0- 6)/(-3 - 0) = - 6/-3 = 2

Slope of line perpendicular to PQ = - 1/2

Since, required line passes through point R(7, - 2) and is perpendicular to PQ.

Therefore, equation of line in point slope form is given as:

\begin{gathered}y - (-2) = - \frac{1}{2} (x - 7) \\ \\ y + 2 = - \frac{1}{2} (x - 7) \\ \\2(y + 2) = - (x - 7) \\ \\ 2y + 4 = - x + 7 \\ \\ 2y + 4 + x - 7 = 0 \\ \\ x + 2y - 3 = 0\end{gathered}

y−(−2)=−

2

1

(x−7)

y+2=−

2

1

(x−7)

2(y+2)=−(x−7)

2y+4=−x+7

2y+4+x−7=0

x+2y−3=0

Therefore x + 2y - 3 = 0 is the required equation of line.

hope it helps you