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2 years ago

Helppppppppp plssssssssss

Mathematics

1 answer:

Tresset [83]2 years ago

4 0

A. Is the answer of this question

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As one of her chores, Staci must vacuum 1/2 of the house. If she already has vacuumed 1/3 of her share tonight, what part of the

Art [367]

Answer:

1/6 has been vacummed.

Step-by-step explanation:

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3 years ago

PLEASE HELP WITH GEOMETRY QUESTION!! FIND H

Yakvenalex [24]

Answer:

we have

when

base=8cm

height=11cm

area of parallelogram is :base×height

=8*11=88cm³

Now for

base=15cm

height=h

we have

the area of parallelogram=88cm²

base ×height=88cm²

15*h=88

h=88/15

h=88/15 or 5 13/15 or 5.86 cm in approximately

3 0

3 years ago

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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . <em>The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.</em>

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3 years ago

Solve x2 + 2x + 9 = 0

Keith_Richards [23]

$x^2+2x+9=0 \\ \\
a=1 \\ b=2 \\ c=9 \\ b^2-4ac=2^2-4 \times 1 \times 9=4-36=-32 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-2 \pm \sqrt{-32}}{2 \times 1}=\frac{-2 \pm \sqrt{-16 \times 2}}{2}=\frac{-2 \pm 4i\sqrt{2}}{2}=-1 \pm 2i\sqrt{2}$

The answer is D.

8 0

3 years ago

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Anyone know how to work this problem? I need to find the domain and range

tamaranim1 [39]

Answer:

Step-by-step explanation:

Domain : [-9,-3]

Range: [2,6]

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3 years ago

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