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TiliK225 [7]
2 years ago
8

Helppppppppp plssssssssss

Mathematics
1 answer:
Tresset [83]2 years ago
4 0

A. Is the answer of this question

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Functions Question (image attached)
zzz [600]

Answer:

x {}^{2}  \times + 4x

Step-by-step explanation:

f(x + 4) = (x + 4) {}^{2}  - 3(x + 4) - 4 \\  = x {}^{2}  + 8x + 16 - 3x - 12 - 4 \\  = x {}^{2}  + 4x

5 0
3 years ago
The height of a tower and the distance of the point of observation from its foot, both, are increased by 20%. The angle of eleva
makvit [3.9K]

Answer:

decreases

Step-by-step explanation:

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
4 0
2 years ago
Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6.
Radda [10]
First calculate the function of x-2y=6:
x-2y=6 | - x
-2y=6-x | ÷ (-2)
y=0.5x-3

Now you have the function. Because the slope you search is parallel to this one, the slope is the same (in this case 0.5). A slope of 0.5 means for 2 steps to the right go one up. To define the function you are searching you have to find out the y intercept. For this take your point (-2|4). Now go as many steps to the right until you reach the y intercept or x=0 in this case you need 2 steps. So for 2 steps right you go one up. Now you have the y intercept (5).
The resulting function is: f(x) = 0.5+6.
6 0
3 years ago
A gym has 2kg and 5kg weights. There are 10 disks in all. The total weight of 2kg and 5kg disks is equal to 29kg. Find the numbe
Simora [160]

Answer:

no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

Step-by-step explanation:

Let the no of 2kg disks be a.

Let no of 5 kg disks be b.

2a+5b=29

a+b=10

Using substitution, we have

2(10-b) + 5b=29

20-2b+5b=29

20+3b=29

3b=9

b=3

So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

6 0
3 years ago
Please help me with this question.
kow [346]
They are equivalent. combine like terms on the first one and 9x-4x+25 can be simplified to 5x+25.
6 0
2 years ago
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