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andrey2020 [161]
3 years ago
5

Help pleasee its due at 8:00 pm

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

10L

Step-by-step explanation:

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Find the value of 2cosx+1=0;0 less than x less than 360°
ohaa [14]

Answer:

120°; 240°

Step-by-step explanation:

Let's first solve for cosx: 2cosx=-1 \rightarrow cosx=-\frac12 At this point it's just a matter of drawing a circle, and mark where the angle is(please excuse my paint skills, but free hand drawing would be even worse). Red line, is -\frac12 on the cosines, and both the green and blue lines are valid solutions. The green line is a quarter of a circle, plus 30°, or 120°. The blue one is 3/4 of a circle, minus 30 degrees, or 240°.

7 0
3 years ago
Find the diameter of each circle.
Vedmedyk [2.9K]

Answer:

<em>Diameter Length: ( About ) 5.4 km; Option B</em>

Step-by-step explanation:

~ Let us apply the Area of the Circle formula πr^2, where r ⇒ radius of the circle ~

1. We are given that the area of the circle is 22.9 km^2, so let us substitute that value into the area of the circle formula, solving for r ( radius ) ⇒ 22.9 = π * r^2 ⇒ r^2 = 22.9/π ⇒ r^2 = 7.28929639361.... ⇒

<em>radius = ( About ) 2.7</em>

2. The diameter would thus be 2 times that of the radius by definition, and thus is: 2.7 * 2 ⇒ ( About ) 5.4 km

<em>Diameter Length: ( About ) 5.4 km</em>

5 0
3 years ago
Find a number that is divisible by 2,3,5,6,9,and 10
FinnZ [79.3K]
<em>90</em> and all of its multiples are.
4 0
3 years ago
Read 2 more answers
How to solve this question please helpp!!!!!!<br><br><br> Q1. cos -1 ( - √3/2 )
Amiraneli [1.4K]

Answer:

cos(\sqrt{\frac{3}{2} }) or 0.339

Step-by-step explanation:

6 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
sdas [7]

Answer:

-15

Step-by-step explanation:

We proceed as follows;

In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.

Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.

Thus, we have;

2a(b-3) + 5b + _

Now, putting -15 will give us the same expression in the first bracket and this gives us the following;

2a(b-3) + 5b-15

2a(b-3) + 5(b-3)

So we can have ; (2a+5)(b-3)

Hence the constant used is -15

8 0
3 years ago
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