All categories

3 years ago

Identify the slope. A. 4 B. 0 C. 2 D. 1

Mathematics

1 answer:

Zepler [3.9K]3 years ago

4 0

Answer:

2, rise over run. 2/1 =2.

You might be interested in

A line passes through the points (-2, 4) and (6, 16). Which of the following would not be

kvasek [131]

(4,12) is the correct answer

3 0

3 years ago

HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25

Misha Larkins [42]

Answer:

Part A) $A=1.25W^2$

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the rectangular basketball section

W ---> the width of the rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

$A=LW$ ----> equation A

The length of the section will be 1.25 times the width of the section

$L=1.25W$ ----> equation B

substitute equation B in equation A

$A=(1.25W)W\\A=1.25W^2$

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

$A=1.25W^2\\A=245\ ft^2$

$245=1.25W^2$

solve for W

$W^2=245/1.25\\W^2=196\\W=14\ ft$

Find the value of L

substitute the value of W in the equation B

$L=1.25(14)=17.5\ ft$

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet

8 0

3 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20x" id="TexFormula1" title="tan^{-1} x" alt="tan^{-1} x

sladkih [1.3K]

$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

$\frak {\huge{ \frac{1}{1 + {x}^{2} } }}$

Step-by-step explanation:

$\sf let \: f(x) = { \tan }^{ - 1} x \\ \\ \sf f(x + h) = { \tan}^{ - 1} (x + h)$

$\sf f'(x) = \frac{f(x+h) - f(x) }{h}$

$\sf \implies \lim_{ h \to 0 } \frac{ { \tan }^{ - 1}(x + h) - { \tan}^{ - 1}x }{h} \\ \\ \\ \sf \implies \lim_ {h \to 0} \frac{ { \tan}^{ - 1} \frac{x + h - x}{1 + (x + h)x} }{h}$

By using

$\sf { \tan}^{ - 1} x - { \tan}^{ - 1} y = \\ \sf { \tan}^{ - 1} \frac{x - y}{1 + xy} formula$

$\sf \implies \large \lim_{h \to0 } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{h} \\ \\ \\ \sf \implies \large{\lim_{h \to0} } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } \times (1 + hx + {x}^{2} )} \\ \\ \\ \sf \implies \large \lim_{h \to0} \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } } + \lim_{h \to0} \frac{1}{1 + hx + {x}^{2} }$

Now putting the value of h = 0

$\sf \large \implies 0 + \frac{1}{1 + 0 + {x}^{2} } \\ \\ \\ \purple{ \boxed { \implies \frac{1}{1 + {x}^{2} } }}$

6 0

2 years ago

The next model of a sports car will cost 3.8% less than the current model. The current model costs $48,000. How much will the pr

iragen [17]

⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒Answer:

3.8% is $1,824

Step-by-step explanation:

math

6 0

3 years ago

Apply the Pythagorean Theorem to find the distance between points A and C.

galina1969 [7]

Answer:

So the correct option is C ) 58 units.

Also If we require Distance then l(AC) = √58 = 7.615 units

Step-by-step explanation:

Let the Points be

point A( x₁ , y₁) ≡ ( -2 , 1)

point C( x₂ , y₂) ≡ (5 , -2)

To Find:

d(AC) = ?

Solution:

By Applying the Pythagorean Theorem to find the distance between points A and C we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A( x₁ , y₁) ≡ ( -2 , 1) and C( x₂ , y₂) ≡ (5 , -2) we get

$l(AC) = \sqrt{((5-{(-2}))^{2}+(-2-1)^{2} )}\\\\l(AC) = \sqrt{(5+2)^{2}+(-3)^{2}}\\\\l(AC) = \sqrt{(49+9)}\\\\l(AC) = \sqrt{58}\\\\OR\\l(AC)^{2} = 58\ units$

So the correct option is C ) 58 units.

If we require Distance then l(AC) = √58 = 7.615 units

8 0

3 years ago