Answer:
Step-by-step explanation:
Given
Area of a floor = 2040ft²
If Its length is 36ft. longer than its width, then L = W+36
Area = LW
L is the length
W is the width
A < W(W+36)
2040 < W²+36W
0<W²+36W-2040
W²+36W-2040 >0
W = -36±√36²-4(-2040)/2
W = -36±√1296+8160)/2
W = -36±√9456/2
W = -36±97.25/2
W = -36+97.25/2
W = 61.24/2
W > 30.62ft
Since L = W+36
L > 30.62+36
L > 66.62ft
The width of the floor is 30.62ft
The length is 66.62ft
The mathematical sentence would represent the given situation is the width is greater than 30.62ft while the length must be greater than 66.62ft
The possible dimension of the floor is 31ft by 67 ft
The possible areas is 31*67 = 2077ft²
It won't be realistic to get an area of 144sqft because the initial area is greater than 144. Hence the feasible area will be greater than 2040ft²
There are 220 chickens and pigs on the farm.
Answer: 75%.
Step-by-step explanation: 3/4 as a percentage is 75%.
Answer:Mark brainliest please
Answer is - 0.5
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
Hello
The number is more by three than a multiple of of 5 (i.e 5x +3) and more than 2 than a multiple of 4 (ie 4y+2(
Now 5x+3=4y+2
ie 5x +1 =4y
we need to give the lowest pair of values to x and y such that the last equality is satisfied.
By trial, x = 3 and y = 4
thus the number is 5x+3 =5(3)+3 =18=4y+2 =4(4)+2=18
I hope it has helped you.