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3 years ago

Find the measure of angle x. Round your answer to the nearest hundredth. (please type the numerical answer only)

Mathematics

1 answer:

alisha [4.7K]3 years ago

5 0

Answer:

x =28.07

Step-by-step explanation:

tan theta = opp/ adj

tan x =8/15

take the inverse tan of each side

tan ^-1 (tan x) = tan^-1 (8/15)

x = tan^-1 (8/15)

x =28.07248694

To the nearest hundredth

x =28.07

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Step-by-step explanation:

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Read 2 more answers

Determine if events A and B are mutually exclusive.

gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

$P(A) = \frac{1}{4}$

$P(B) = \frac{3}{5}$

$P(A\ or\ B) = \frac{7}{10}$

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}$

Take LCM

$P(A\ or\ B) = \frac{5+12}{20}$

$P(A\ or\ B) = \frac{17}{20}$

By comparing:

$P(A\ or\ B) = \frac{17}{20}$ ---- Calculated

$P(A\ or\ B) = \frac{7}{10}$ ---- Given

We can conclude that A and B are not mutually exclusive because:

$\frac{17}{20} \ne \frac{7}{10}$

6 0

3 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

3 years ago