The slope of the red line that is perpendicular to the green line is: -5/2.
<h3>What are the Slope Values of Perpendicular Lines?</h3>
When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.
<h3>What is the Negative Reciprocal of a Number?</h3>
If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.
Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.
Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.
Negative reciprocal of 2/5 is -5/2.
Therefore, the slope of the red line is: -5/2.
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Answer:
19a^5b^2
Step-by-step explanation:
15a+4a=19a
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Answer:
cubes are 3-d while squares are 2-d so in order to solve them you need different equations.
A line segment can be divided into ratios.
<em>The coordinate of P on line segment AB is (5,1)</em>
Given


The position of P from A to B is:

So, from P to B would be:


So, the ratio is:

Simplify

<u>The coordinate of point P is:</u>

So, we have:



<em>Hence, the coordinate of P is (5,1)</em>
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