Answer:
they are adjacent angles
Step-by-step explanation:
for adjacent angles
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer:
f(x)=5x^3-2x^2-90x-36=0
=x^2(5x-2)-18(5x-2)=(x^2-18)(5x-2)=0
x^2-18=0/5x-2=0
x^2=18=x=9√2
5x-2=0
x=2/5
zeros are 9√2,2/5
Answer:
26
Step-by-step explanation:
