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lesya692 [45]
3 years ago
15

In Problems 41 and 42 solve the given initial-value problem in which the input function g(x) is discontinuous. [Hint: Solve each

problem on two intervals, and then find a solution so that y and y are continuous at x p2 (Problem 41) and at x p (Problem 42).] 41. y 4y g(x), y(0) 1, y(0) 2,
Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer: hello your question is poorly written attached below is the complete question

answer:

attached below

Step-by-step explanation:

using

m^2 - 2m + 10 = 0

m = 2± (√4 - 4(1)(10)) / (2(1)) = 1 ± 3i

Hence the complementary function ; Yc = e^x ( C1 cos3x + C2 sin3x )

attached below is the detailed solution

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Answer:

y=5 \ \ \ x x_o + 1.9s

Step-by-step explanation:

This situation can be considered as a piecewise function. First, you take xo as the time in which the drone goes upward. Before this time the height of the drone is constant with a value of 5 m. Next, you take into account that during 1.9 s after xo the drone accelerates. Finally, the drone flies again with a constant height of 5.9m. Hence, this function has three parts:

For the first part you have:

y = 5       for x <  xo

For the second part you first calculate vertical speed (which means the slope of the linear function) by using the following kinematic equation:

y=vx\\\\v=\frac{y-y_o}{x}=\frac{5.9m-5.0m}{1.9s}=0.47m/s

Then you have:

y = 0.47x    for xo < x < xo + 1.9s

And for the third part:

y = 5.9    for x > xo  + 1.9s

Summarizing you obtain:

y=5 \ \ \ x x_o + 1.9s

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