If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
The table of values of the function y = 2x^2 is:
x 0 1 2 3 4
y 0 2 8 18 32
<h3>How to complete the table?</h3>
The equation of the function is given as:
y = 2x^2
When x= 0, we have
y = 2 * 0^2 = 0
When x= 1, we have
y = 2 * 1^2 = 2
When x= 2, we have
y = 2 * 2^2 = 8
When x= 3, we have
y = 2 * 3^2 = 18
When x= 4, we have
y = 2 * 4^2 = 32
So, the table of values is:
x 0 1 2 3 4
y 0 2 8 18 32
Read more about functions and tables at:
brainly.com/question/15602982
#SPJ1
Answer:
Like 3/5? Or something?
Step-by-step explanation:
Jk that's 63%
Good luck!