At the end of the 2nd yr his balance is $440, = I = $14.08
At the end if the 3rd yr his balance is $600, = I = $21.12
$200 is deposited at the beginning of each year
End if the 1st yr SI = PRT/100 = 220 X 3.2 X 1/100 = $7.04
Start of the 2nd yr $220 + $220 = $440
End of the 2nd yr: SI = PRT/100 = 440 X 3.2 X 1/100 = $14.08
Start of the 3rd yr $440 + $220 = $660
End of the 3rd yr: SI = PRT/100 = 660X 3.2 X 1/100 = $21.12
At the end of th2 2nd yr his balance is 440, = I = $14.08
At the end if the 3rd yr his balance is $600, = I = $21.12
HE now has $660 in his account and has earned a total of 42.24 interest over the 3 years.
Step-by-step explanation:
You need to attach the table in order to get an answer.
You don't even have to actually do the division to find the correct answer.
The leading term of q(x) is x³/x² = x, so only the 1st and 3rd selections are appropriate.
The remainder r(x)/b(x) will have the divisor as b(x), so only ...
.. the 1st selection is appropriate.
Answer:
We know that C is the total number of cans in a complete case.
Victoria counts:
16 full cases, so in those we have: 16*C cans.
4 cases with 5 missing cans, so in those we have:
Then if each case has C cans, the cases that are missing 5 cans have:
C - 5 cans.
Then in those four cases we have a total of: 4*(C - 5) cans.
And Victoria knows that there are 220 cans, then we have that:
16*C + 4*(C - 5) = 220
16*C + 4*C - 20 = 220
16*C + 4*C = 220 + 20 = 240
20*C = 240
C = 240/20 = 12
Then each case has 12 cans.
Then the number of cans in the cases with missing cans is:
12 cans - 5 cans = 7 cans.
Step-by-step explanation:
Hope this helps!!!!!!!! :D
Answer:1866
Step-by-step explanation:
Given
n=200
x=118
Population proportion P=
=0.59
=0.005
Realiability =99%
Margin of erroe is given by 
0.03= 
85.667=![\sqrt{\frac{N}{0.6519}}[tex]N=1865.88[tex]\approx 1866 Students](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BN%7D%7B0.6519%7D%7D%5Btex%5D%3C%2Fp%3E%3Cp%3EN%3D1865.88%5Btex%5D%5Capprox%201866%20Students)
