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ad-work [718]
3 years ago
11

Consider the polynomial P(x)=x⁴+3x³-28x²-36x+144. Write the equation of P in factored form.

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

P(x)=(x-2)(x-4)(x+3)(x+6)

Step-by-step explanation:

Given: P(x)=x⁴+3x³-28x²-36x+144

It is a polynomial with degree 4.

It should maximum four factor.

Hit and trial error method.

Put x = 2 into P(x)

P(2)=2⁴+3×2³-28×2²-36×2+144

P(2) = 0

So, x-2 would be factor of P(x)

Now divide x⁴+3x³-28x²-36x+144 by x-2 to get another factors

(x^4+3x^3-28x^2-36x+144)\div (x-2) = x^3+5x^2-18x-72

P(x)=(x-2)(x^3+5x^2-18x-72)

Put x = 4

P(4) = 0

now divide x^3+5x^2-18x-72 by x-4

(x^3+5x^2-18x-72)\div (x-4) = x^2+9x+18

P(x)=(x-2)(x-4)(x^2+9x+18)

Now factor x^2+9x+18

\Rightarrow x^2+9x+18

\Rightarrow (x+6)(x+3)

Complete factor of P(x)

P(x)=(x-2)(x-4)(x+3)(x+6)

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5

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2

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14

x

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10

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3

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80

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4

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280

x

3

+

45

x

2

−

8

x

2

−

350

x

−

14

x

+

125

+

10

+

3

f

(

g

(

x

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)

=

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x

4

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280

x

3

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2

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g

(

x

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)

=

80

x

4

+

280

x

3

+

37

x

2

−

364

x

+

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