Answer:
<h2><u><em>
If the number of statements following the for/if is single you don't have to use curly braces</em></u>. </h2>
Explanation:
But if the number of statements is more than one, then you need to use curly braces.
<h2><u><em>
BRAINLIEST please <3</em></u></h2>
<u><em></em></u>
<u><em>so its</em></u>
<h2><u><em>
NO</em></u></h2>
<h2>
Answer:</h2><h2>#include <iostream>
</h2><h2>using namespace std;
</h2><h2>
</h2><h2>int main()
</h2><h2>{
</h2><h2> char c;
</h2><h2> int isLowercaseVowel, isUppercaseVowel;
</h2><h2>
</h2><h2> cout << "Enter an alphabet: ";
</h2><h2> cin >> c;
</h2><h2>
</h2><h2> // evaluates to 1 (true) if c is a lowercase vowel
</h2><h2> isLowercaseVowel = (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');
</h2><h2>
</h2><h2> // evaluates to 1 (true) if c is an uppercase vowel
</h2><h2> isUppercaseVowel = (c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');
</h2><h2>
</h2><h2> // evaluates to 1 (true) if either isLowercaseVowel or isUppercaseVowel is true
</h2><h2> if (isLowercaseVowel || isUppercaseVowel)
</h2><h2> cout << c << " is a vowel.";
</h2><h2> else
</h2><h2> cout << c << " is a consonant.";
</h2><h2>
</h2><h2> return 0;
</h2><h2>}</h2>
Explanation:
True. That data is called binary
