Answer:
-3q² + 3qp + 2rp - 2rq + Sq - Sp
Step-by-step explanation:
first part
3q(p-q) = 3qp - 3q²
second part
2r(p-q) = 2rp - 2rq
third part
S(q-p) = Sq - Sp
then we put it all together
3qp - 3q² + 2rp - 2rq + Sq - Sp
in the right place possibly
-3q² + 3qp + 2rp - 2rq + Sq - Sp
A) In Part 1 to part 2 the bus had its farthest distance. At part 2 the bus stayed steady time went by. Part 3 to 4 was decreasing distance. part 4 was constant. Then again at part 5 the distance was increasing
B)
1 - increasing
2 - constant
3 - decreasing
4 - constant
5 - increasing
C) Non-linear, because the graph has a curve, for it to be linear it must be a straight line.
Hope this Helps :)
Answer:
Step-by-step explanation:
We have been given that Vladimir is walking down the street at a speed of 4 miles per hour. We are asked to write an for the distance in miles, d, that Vladimir walks over time in hours, t.
We will use rate formula to solve our given problem.
Upon substituting our given information in distance equation, we will get:
Therefore, the equation represents the distance that Vladimir walks over time in hours.
Answer:
1=S
2=T
3=U
4=V
5=W
6=X
7=Y
8=Z
Step-by-step explanation:
I learned about coordinate planes so this will help, sorry if its wrong
Answer:
Its 1
Step-by-step explanation:
