Answer:
No, the maximum height that the balloon can reach is 9ft.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
The function h(x) =-0.5(x-4)² +9, is a Quadratic Function in the Vertex form.
Vertex form: f (x) = a(x - h) 2 + k
Where:
- (h, k) is the vertex of the parabola-
- h is the horizontal shift (how far left, or right, the graph has shifted from x = 0).
- k represents the vertical shift (how far up, or down, the graph has shifted from y = 0).
In this case a = -0.5, it means that the parabola opens downward and has a maximum point at the vertex.
So, the maximum height that the balloon can reach is k=9ft.
9 ∠ 12
The balloon will not hit the ceiling 12 ft above the pool.
Feel free to ask for more if needed or if you did not understand something.
Answer:
8.2% of 500 = 41
Step-by-step explanation:
Set up the equation. On a piece of paper, write the dividend (number being divided) on the right, under the division symbol, and the divisor (number doing the division) to the left on the outside. ...
Divide the first digit. ...
Divide the first two digits. ...
Enter the first digit of the quotient.
D. 1/3
A cube root can be written as an exponent: 1/3
![\sqrt[3]{x} = x^{\frac{1}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
we know that
total of sum of arc is 360
so, sum of both arc must be 360
so, we get
now, we can solve for x
............Answer
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
