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fiasKO [112]
3 years ago
5

Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×

b+50 approximates the relationship between scores on the two tests. use the summary statistics for a sample of students who took test b to determine the summary statistics for equivalent scores on test
a. lowest score equals= 2121 mean equals= 2929 standard deviation equals= 22 q3 equals= 2828 median equals= 2626 iqr equals= 66 find the summary statistics for equivalent scores on test
a. lowest scoreequals= nothing meanequals= nothing standard deviationequals= nothing q3equals= nothing medianequals= nothing iqrequals= nothing
Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

Thus, the standard deviation of  test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

A=40B+50\\=(40\times28)+50\\=1170

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

A=40B+50\\=(40\times26)+50\\=1090

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

A=40B+50\\=(40\times6)+50\\=290

Thus, the value of IQR for test A is 290.

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Nookie1986 [14]

Minimum = 18, Q₁ = 27.5, median = 39.5, Q₃ = 43, maximum = 49.

The five-number summary is a descriptive statistic that provides information on a series of observations. It consists of the following statistics:

1. Minimum: the smallest observation

2. First quartile  Q₁: the average of the values ​​below the median.

3. Medium  M: the average term.

4. third quartile  Q₃: the average of values ​​above the median.

5. Maximum: The largest observation.

The data represents the numbers of runs allowed by 8 college pitchers.

{18, 49, 38, 41, 33, 44, 42, 22}

The five-number summary is:

First, we have to sort the data from least to greatest.

{18, 22, 33, 38, 41, 42, 44, 49}

From the ordered data we can see that the minimum value is 18 and the maximum is 49.

The median is the middle term of the data set. In this case of an even number of terms, the median is the average of the terms located in the middle. So, the terms located in the middle if the data are in bold:

{18, 22, 33, 38, 41, 42, 44, 49}

Median= (38 + 41)/2 = 79/2 = 39.5

To calculate the first quartile Q₁, the values ​​below the median are {18, 22, 33, 38}. So, the median of this values is the first quartile Q₁:

{18, 22, 33, 38}

Q₁ = (22 + 33)/2 = 55/2 = 27.5

To calculate the third quartile  Q₃, the values ​​above the median are {41, 42, 44, 49}. So, the median of this values is the third quartile Q₃:

{41, 42, 44, 49}

Q₃ = (42 + 44)/2 = 86/2 = 43

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A = (pi) 6^2

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