All categories

3 years ago

Direct Variation.¯\_(ツ)_/¯

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

5 0

Answer:

y = 1/6

Step-by-step explanation:

direct variation

y =kx

substitute in what we know to find k

1/2 = k*3

solve for k

divide by 3

1/2 /3 = k

1/6 = k

substitute k into the direct variation equation

y = 1/6 x

let x = 1

y = 1/6 *1

y = 1/6

You might be interested in

(solve) 12 1/2-(-4 1/2) =

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

12 1/2 -(-4 1/2) = 12 1/2 + 4 1/2

=25/2 + 9/2

= 34 /2

= 17

8 0

3 years ago

There was 7 girls in a bus and each girl have 7 bags and in each bag there is 7 cats and each cat is pregnant with 7 kittens how

rodikova [14]

33614 that is the biggest waste of my time

3 0

3 years ago

Read 2 more answers

Show that B = {[a, b) ⊂ ℝ | a < b} is a basis for a topology on ℝ

loris [4]

Answer:

Remember that a set $\mathcal{B}$ is a base for some topology on $\mathbb{R}$ if satisfy the following properties:

1. $\mathbb{R}=\cup\{B: B\in\mathcal{B}\}$

2. For $B, B^* \in \mathcal{B}$ , If $p\in B\cap B^*$ then exist $B_p\in\mathcal{B}$ such that $p\in B_p\subset B\cap B^*$ .

Now, for $B=\{[a,b)\subset\mathbb{R}| a < b\}$ we verify the above properties:

1. It's clear that $\mathbb{R}=\cup_{a,b \text{ with }a$

2. Let $B=[a,b), B^*=[c,d) \in \mathcal{B}, p\in B\cap B^*$ . Without loss of generality suppose that $a$ . Then $c\leq p < b$ , this implies that $p\in[c,b)$ and $B_p=[c,d) \in \mathcal{B}$ and $B_p\subset B\cap B^*$ .

Then, B satisfy the two properties. This show that B is a basis for a topology in $\mathbb{R}$

6 0

3 years ago

Marcie solved the following inequality and her work is shown below:. . −2(x − 5) − 12 ≤ 4 + 6(x + 3). −2x + 10 − 12 ≤ 4 + 6x + 1

BartSMP [9]

All steps that Marcie did are right, but she forgot to change sign in last step.

Consider the inequality

$-2(x - 5) -12 \le 4 + 6(x + 3).$

Then

$-2x+10-12 \le 4 + 6x+18.$

Group the numbers:

$-2x-2 \le 6x+22.$

Separate terms with x and without x in different sides:

$-2x-6x \le 22+2.\\-8x\le 24.$

The coefficient at x is -8 and it is negative, then dividing the inequality by -8 you have to change sign in opposite:

$x\ge -3.$

Answer: Marcie forgot to change sign in last step.

3 0

3 years ago

Read 2 more answers

Number 1 please <br> Add the number in each set<br> A 20,30,50,<br> B 3,9,7,4,1

Nataly [62]

Answer:

a=110 b=24

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers